Optimal. Leaf size=154 \[ \frac {(a+b) \left (5 a^2-2 a b+5 b^2\right ) \text {ArcTan}(\sinh (c+d x))}{16 d}+\frac {(a-b) \left (15 a^2+14 a b+15 b^2\right ) \text {sech}(c+d x) \tanh (c+d x)}{48 d}+\frac {5 \left (a^2-b^2\right ) \text {sech}^3(c+d x) \left (a+b \sinh ^2(c+d x)\right ) \tanh (c+d x)}{24 d}+\frac {(a-b) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2 \tanh (c+d x)}{6 d} \]
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Rubi [A]
time = 0.10, antiderivative size = 154, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {3269, 424, 540,
393, 209} \begin {gather*} \frac {(a+b) \left (5 a^2-2 a b+5 b^2\right ) \text {ArcTan}(\sinh (c+d x))}{16 d}+\frac {(a-b) \left (15 a^2+14 a b+15 b^2\right ) \tanh (c+d x) \text {sech}(c+d x)}{48 d}+\frac {5 \left (a^2-b^2\right ) \tanh (c+d x) \text {sech}^3(c+d x) \left (a+b \sinh ^2(c+d x)\right )}{24 d}+\frac {(a-b) \tanh (c+d x) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2}{6 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 209
Rule 393
Rule 424
Rule 540
Rule 3269
Rubi steps
\begin {align*} \int \text {sech}^7(c+d x) \left (a+b \sinh ^2(c+d x)\right )^3 \, dx &=\frac {\text {Subst}\left (\int \frac {\left (a+b x^2\right )^3}{\left (1+x^2\right )^4} \, dx,x,\sinh (c+d x)\right )}{d}\\ &=\frac {(a-b) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2 \tanh (c+d x)}{6 d}+\frac {\text {Subst}\left (\int \frac {\left (a+b x^2\right ) \left (a (5 a+b)+b (a+5 b) x^2\right )}{\left (1+x^2\right )^3} \, dx,x,\sinh (c+d x)\right )}{6 d}\\ &=\frac {5 \left (a^2-b^2\right ) \text {sech}^3(c+d x) \left (a+b \sinh ^2(c+d x)\right ) \tanh (c+d x)}{24 d}+\frac {(a-b) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2 \tanh (c+d x)}{6 d}-\frac {\text {Subst}\left (\int \frac {-a \left (15 a^2+4 a b+5 b^2\right )-b \left (5 a^2+4 a b+15 b^2\right ) x^2}{\left (1+x^2\right )^2} \, dx,x,\sinh (c+d x)\right )}{24 d}\\ &=\frac {(a-b) \left (15 a^2+14 a b+15 b^2\right ) \text {sech}(c+d x) \tanh (c+d x)}{48 d}+\frac {5 \left (a^2-b^2\right ) \text {sech}^3(c+d x) \left (a+b \sinh ^2(c+d x)\right ) \tanh (c+d x)}{24 d}+\frac {(a-b) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2 \tanh (c+d x)}{6 d}+\frac {\left ((a+b) \left (5 a^2-2 a b+5 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sinh (c+d x)\right )}{16 d}\\ &=\frac {(a+b) \left (5 a^2-2 a b+5 b^2\right ) \tan ^{-1}(\sinh (c+d x))}{16 d}+\frac {(a-b) \left (15 a^2+14 a b+15 b^2\right ) \text {sech}(c+d x) \tanh (c+d x)}{48 d}+\frac {5 \left (a^2-b^2\right ) \text {sech}^3(c+d x) \left (a+b \sinh ^2(c+d x)\right ) \tanh (c+d x)}{24 d}+\frac {(a-b) \text {sech}^5(c+d x) \left (a+b \sinh ^2(c+d x)\right )^2 \tanh (c+d x)}{6 d}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 13.52, size = 1192, normalized size = 7.74 \begin {gather*} \frac {\text {csch}^5(c+d x) \left (-117228825 a^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right )-109265625 a^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^2(c+d x)-274542345 a^2 b \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^2(c+d x)-17069535 a^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^4(c+d x)-260465625 a^2 b \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^4(c+d x)-215549775 a b^2 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^4(c+d x)+142065 a^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^6(c+d x)-41427855 a^2 b \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^6(c+d x)-207173295 a b^2 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^6(c+d x)-58009455 b^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^6(c+d x)-210735 a^2 b \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^8(c+d x)-33756345 a b^2 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^8(c+d x)-56109375 b^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^8(c+d x)-174825 a b^2 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^{10}(c+d x)-9261945 b^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^{10}(c+d x)-48825 b^3 \tanh ^{-1}\left (\sqrt {-\sinh ^2(c+d x)}\right ) \sinh ^{12}(c+d x)+117228825 a^3 \sqrt {-\sinh ^2(c+d x)}+4093425 a^3 \sinh ^4(c+d x) \sqrt {-\sinh ^2(c+d x)}+168951510 a^2 b \sinh ^4(c+d x) \sqrt {-\sinh ^2(c+d x)}+215549775 a b^2 \sinh ^4(c+d x) \sqrt {-\sinh ^2(c+d x)}+9514449 a^2 b \sinh ^6(c+d x) \sqrt {-\sinh ^2(c+d x)}+135323370 a b^2 \sinh ^6(c+d x) \sqrt {-\sinh ^2(c+d x)}+58009455 b^3 \sinh ^6(c+d x) \sqrt {-\sinh ^2(c+d x)}+7808535 a b^2 \sinh ^8(c+d x) \sqrt {-\sinh ^2(c+d x)}+36772890 b^3 \sinh ^8(c+d x) \sqrt {-\sinh ^2(c+d x)}+2160711 b^3 \sinh ^{10}(c+d x) \sqrt {-\sinh ^2(c+d x)}-70189350 a^3 \left (-\sinh ^2(c+d x)\right )^{3/2}-274542345 a^2 b \left (-\sinh ^2(c+d x)\right )^{3/2}+1024 a^3 \, _7F_6\left (\frac {3}{2},2,2,2,2,2,2;1,1,1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^6(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2}+3072 a^2 b \, _7F_6\left (\frac {3}{2},2,2,2,2,2,2;1,1,1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^8(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2}+3072 a b^2 \, _7F_6\left (\frac {3}{2},2,2,2,2,2,2;1,1,1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^{10}(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2}+1024 b^3 \, _7F_6\left (\frac {3}{2},2,2,2,2,2,2;1,1,1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^{12}(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2}+1536 \, _6F_5\left (\frac {3}{2},2,2,2,2,2;1,1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^6(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2} \left (a+b \sinh ^2(c+d x)\right )^2 \left (9 a+7 b \sinh ^2(c+d x)\right )+256 \, _5F_4\left (\frac {3}{2},2,2,2,2;1,1,1,\frac {11}{2};-\sinh ^2(c+d x)\right ) \sinh ^6(c+d x) \left (-\sinh ^2(c+d x)\right )^{3/2} \left (295 a^3+741 a^2 b \sinh ^2(c+d x)+621 a b^2 \sinh ^4(c+d x)+175 b^3 \sinh ^6(c+d x)\right )\right )}{725760 d \sqrt {-\sinh ^2(c+d x)}} \end {gather*}
Warning: Unable to verify antiderivative.
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Maple [C] Result contains complex when optimal does not.
time = 1.78, size = 495, normalized size = 3.21
method | result | size |
risch | \(\frac {{\mathrm e}^{d x +c} \left (15 a^{3} {\mathrm e}^{10 d x +10 c}+9 a^{2} b \,{\mathrm e}^{10 d x +10 c}+9 a \,b^{2} {\mathrm e}^{10 d x +10 c}-33 b^{3} {\mathrm e}^{10 d x +10 c}+85 a^{3} {\mathrm e}^{8 d x +8 c}+51 a^{2} b \,{\mathrm e}^{8 d x +8 c}-141 a \,b^{2} {\mathrm e}^{8 d x +8 c}+5 b^{3} {\mathrm e}^{8 d x +8 c}+198 a^{3} {\mathrm e}^{6 d x +6 c}-342 a^{2} b \,{\mathrm e}^{6 d x +6 c}+234 a \,b^{2} {\mathrm e}^{6 d x +6 c}-90 b^{3} {\mathrm e}^{6 d x +6 c}-198 a^{3} {\mathrm e}^{4 d x +4 c}+342 a^{2} b \,{\mathrm e}^{4 d x +4 c}-234 a \,b^{2} {\mathrm e}^{4 d x +4 c}+90 b^{3} {\mathrm e}^{4 d x +4 c}-85 a^{3} {\mathrm e}^{2 d x +2 c}-51 a^{2} b \,{\mathrm e}^{2 d x +2 c}+141 a \,b^{2} {\mathrm e}^{2 d x +2 c}-5 b^{3} {\mathrm e}^{2 d x +2 c}-15 a^{3}-9 a^{2} b -9 a \,b^{2}+33 b^{3}\right )}{24 d \left (1+{\mathrm e}^{2 d x +2 c}\right )^{6}}+\frac {5 i \ln \left ({\mathrm e}^{d x +c}+i\right ) a^{3}}{16 d}+\frac {3 i \ln \left ({\mathrm e}^{d x +c}+i\right ) a^{2} b}{16 d}+\frac {3 i \ln \left ({\mathrm e}^{d x +c}+i\right ) a \,b^{2}}{16 d}+\frac {5 i \ln \left ({\mathrm e}^{d x +c}+i\right ) b^{3}}{16 d}-\frac {5 i \ln \left ({\mathrm e}^{d x +c}-i\right ) a^{3}}{16 d}-\frac {3 i \ln \left ({\mathrm e}^{d x +c}-i\right ) a^{2} b}{16 d}-\frac {3 i \ln \left ({\mathrm e}^{d x +c}-i\right ) a \,b^{2}}{16 d}-\frac {5 i \ln \left ({\mathrm e}^{d x +c}-i\right ) b^{3}}{16 d}\) | \(495\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 646 vs.
\(2 (146) = 292\).
time = 0.50, size = 646, normalized size = 4.19 \begin {gather*} -\frac {1}{24} \, b^{3} {\left (\frac {15 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} + \frac {33 \, e^{\left (-d x - c\right )} - 5 \, e^{\left (-3 \, d x - 3 \, c\right )} + 90 \, e^{\left (-5 \, d x - 5 \, c\right )} - 90 \, e^{\left (-7 \, d x - 7 \, c\right )} + 5 \, e^{\left (-9 \, d x - 9 \, c\right )} - 33 \, e^{\left (-11 \, d x - 11 \, c\right )}}{d {\left (6 \, e^{\left (-2 \, d x - 2 \, c\right )} + 15 \, e^{\left (-4 \, d x - 4 \, c\right )} + 20 \, e^{\left (-6 \, d x - 6 \, c\right )} + 15 \, e^{\left (-8 \, d x - 8 \, c\right )} + 6 \, e^{\left (-10 \, d x - 10 \, c\right )} + e^{\left (-12 \, d x - 12 \, c\right )} + 1\right )}}\right )} - \frac {1}{24} \, a^{3} {\left (\frac {15 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} - \frac {15 \, e^{\left (-d x - c\right )} + 85 \, e^{\left (-3 \, d x - 3 \, c\right )} + 198 \, e^{\left (-5 \, d x - 5 \, c\right )} - 198 \, e^{\left (-7 \, d x - 7 \, c\right )} - 85 \, e^{\left (-9 \, d x - 9 \, c\right )} - 15 \, e^{\left (-11 \, d x - 11 \, c\right )}}{d {\left (6 \, e^{\left (-2 \, d x - 2 \, c\right )} + 15 \, e^{\left (-4 \, d x - 4 \, c\right )} + 20 \, e^{\left (-6 \, d x - 6 \, c\right )} + 15 \, e^{\left (-8 \, d x - 8 \, c\right )} + 6 \, e^{\left (-10 \, d x - 10 \, c\right )} + e^{\left (-12 \, d x - 12 \, c\right )} + 1\right )}}\right )} - \frac {1}{8} \, a^{2} b {\left (\frac {3 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} - \frac {3 \, e^{\left (-d x - c\right )} + 17 \, e^{\left (-3 \, d x - 3 \, c\right )} - 114 \, e^{\left (-5 \, d x - 5 \, c\right )} + 114 \, e^{\left (-7 \, d x - 7 \, c\right )} - 17 \, e^{\left (-9 \, d x - 9 \, c\right )} - 3 \, e^{\left (-11 \, d x - 11 \, c\right )}}{d {\left (6 \, e^{\left (-2 \, d x - 2 \, c\right )} + 15 \, e^{\left (-4 \, d x - 4 \, c\right )} + 20 \, e^{\left (-6 \, d x - 6 \, c\right )} + 15 \, e^{\left (-8 \, d x - 8 \, c\right )} + 6 \, e^{\left (-10 \, d x - 10 \, c\right )} + e^{\left (-12 \, d x - 12 \, c\right )} + 1\right )}}\right )} - \frac {1}{8} \, a b^{2} {\left (\frac {3 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} - \frac {3 \, e^{\left (-d x - c\right )} - 47 \, e^{\left (-3 \, d x - 3 \, c\right )} + 78 \, e^{\left (-5 \, d x - 5 \, c\right )} - 78 \, e^{\left (-7 \, d x - 7 \, c\right )} + 47 \, e^{\left (-9 \, d x - 9 \, c\right )} - 3 \, e^{\left (-11 \, d x - 11 \, c\right )}}{d {\left (6 \, e^{\left (-2 \, d x - 2 \, c\right )} + 15 \, e^{\left (-4 \, d x - 4 \, c\right )} + 20 \, e^{\left (-6 \, d x - 6 \, c\right )} + 15 \, e^{\left (-8 \, d x - 8 \, c\right )} + 6 \, e^{\left (-10 \, d x - 10 \, c\right )} + e^{\left (-12 \, d x - 12 \, c\right )} + 1\right )}}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 3675 vs.
\(2 (146) = 292\).
time = 0.44, size = 3675, normalized size = 23.86 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 383 vs.
\(2 (146) = 292\).
time = 0.46, size = 383, normalized size = 2.49 \begin {gather*} \frac {3 \, {\left (\pi + 2 \, \arctan \left (\frac {1}{2} \, {\left (e^{\left (2 \, d x + 2 \, c\right )} - 1\right )} e^{\left (-d x - c\right )}\right )\right )} {\left (5 \, a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + 5 \, b^{3}\right )} + \frac {4 \, {\left (15 \, a^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{5} + 9 \, a^{2} b {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{5} + 9 \, a b^{2} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{5} - 33 \, b^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{5} + 160 \, a^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{3} + 96 \, a^{2} b {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{3} - 96 \, a b^{2} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{3} - 160 \, b^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{3} + 528 \, a^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )} - 144 \, a^{2} b {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )} - 144 \, a b^{2} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )} - 240 \, b^{3} {\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}\right )}}{{\left ({\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{2} + 4\right )}^{3}}}{96 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.20, size = 601, normalized size = 3.90 \begin {gather*} \frac {\mathrm {atan}\left (\frac {{\mathrm {e}}^{d\,x}\,{\mathrm {e}}^c\,\left (5\,a^3\,\sqrt {d^2}+5\,b^3\,\sqrt {d^2}+3\,a\,b^2\,\sqrt {d^2}+3\,a^2\,b\,\sqrt {d^2}\right )}{d\,\sqrt {25\,a^6+30\,a^5\,b+39\,a^4\,b^2+68\,a^3\,b^3+39\,a^2\,b^4+30\,a\,b^5+25\,b^6}}\right )\,\sqrt {25\,a^6+30\,a^5\,b+39\,a^4\,b^2+68\,a^3\,b^3+39\,a^2\,b^4+30\,a\,b^5+25\,b^6}}{8\,\sqrt {d^2}}-\frac {6\,{\mathrm {e}}^{c+d\,x}\,\left (3\,a^3-11\,a^2\,b+13\,a\,b^2-5\,b^3\right )}{d\,\left (4\,{\mathrm {e}}^{2\,c+2\,d\,x}+6\,{\mathrm {e}}^{4\,c+4\,d\,x}+4\,{\mathrm {e}}^{6\,c+6\,d\,x}+{\mathrm {e}}^{8\,c+8\,d\,x}+1\right )}+\frac {{\mathrm {e}}^{c+d\,x}\,\left (a^3-57\,a^2\,b+111\,a\,b^2-55\,b^3\right )}{3\,d\,\left (3\,{\mathrm {e}}^{2\,c+2\,d\,x}+3\,{\mathrm {e}}^{4\,c+4\,d\,x}+{\mathrm {e}}^{6\,c+6\,d\,x}+1\right )}+\frac {{\mathrm {e}}^{c+d\,x}\,\left (5\,a^3+3\,a^2\,b+3\,a\,b^2-11\,b^3\right )}{8\,d\,\left ({\mathrm {e}}^{2\,c+2\,d\,x}+1\right )}+\frac {{\mathrm {e}}^{c+d\,x}\,\left (5\,a^3+3\,a^2\,b-93\,a\,b^2+85\,b^3\right )}{12\,d\,\left (2\,{\mathrm {e}}^{2\,c+2\,d\,x}+{\mathrm {e}}^{4\,c+4\,d\,x}+1\right )}+\frac {80\,{\mathrm {e}}^{c+d\,x}\,\left (a^3-3\,a^2\,b+3\,a\,b^2-b^3\right )}{3\,d\,\left (5\,{\mathrm {e}}^{2\,c+2\,d\,x}+10\,{\mathrm {e}}^{4\,c+4\,d\,x}+10\,{\mathrm {e}}^{6\,c+6\,d\,x}+5\,{\mathrm {e}}^{8\,c+8\,d\,x}+{\mathrm {e}}^{10\,c+10\,d\,x}+1\right )}-\frac {32\,{\mathrm {e}}^{c+d\,x}\,\left (a^3-3\,a^2\,b+3\,a\,b^2-b^3\right )}{3\,d\,\left (6\,{\mathrm {e}}^{2\,c+2\,d\,x}+15\,{\mathrm {e}}^{4\,c+4\,d\,x}+20\,{\mathrm {e}}^{6\,c+6\,d\,x}+15\,{\mathrm {e}}^{8\,c+8\,d\,x}+6\,{\mathrm {e}}^{10\,c+10\,d\,x}+{\mathrm {e}}^{12\,c+12\,d\,x}+1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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